2x^2+12x-32=908

Solution for 2x^2+12x-32=908 equation:

2x^2+12x-32=908

We move all terms to the left:

2x^2+12x-32-(908)=0

We add all the numbers together, and all the variables

2x^2+12x-940=0

a = 2; b = 12; c = -940;
Δ = b2-4ac
Δ = 122-4·2·(-940)
Δ = 7664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7664}=\sqrt{16*479}=\sqrt{16}*\sqrt{479}=4\sqrt{479}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{479}}{2*2}=\frac{-12-4\sqrt{479}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{479}}{2*2}=\frac{-12+4\sqrt{479}}{4}
$